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2-2-2-2-2-X-2-2-2-2-2-5-10-5-2-V-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-5-Variance-0-

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Question Number 118775 by obaidullah last updated on 19/Oct/20
2,2,2,2,2 X=((2+2+2+2+2)/5)=((10)/5)=2 V=(((2−2)^2 +(2−2)^2 +(2−2)^2 +(2−2)^2 +(2−2)^2 )/5) Variance=0
2,2,2,2,2X=2+2+2+2+25=105=2V=(2−2)2+(2−2)2+(2−2)2+(2−2)2+(2−2)25Variance=0

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