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2-2-2-2-2-X-2-2-2-2-2-5-10-5-2-V-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-5-Variance-0-




Question Number 118775 by obaidullah last updated on 19/Oct/20
2,2,2,2,2  X=((2+2+2+2+2)/5)=((10)/5)=2  V=(((2−2)^2 +(2−2)^2 +(2−2)^2 +(2−2)^2 +(2−2)^2 )/5)  Variance=0
$$\mathrm{2},\mathrm{2},\mathrm{2},\mathrm{2},\mathrm{2} \\ $$$${X}=\frac{\mathrm{2}+\mathrm{2}+\mathrm{2}+\mathrm{2}+\mathrm{2}}{\mathrm{5}}=\frac{\mathrm{10}}{\mathrm{5}}=\mathrm{2} \\ $$$${V}=\frac{\left(\mathrm{2}−\mathrm{2}\right)^{\mathrm{2}} +\left(\mathrm{2}−\mathrm{2}\right)^{\mathrm{2}} +\left(\mathrm{2}−\mathrm{2}\right)^{\mathrm{2}} +\left(\mathrm{2}−\mathrm{2}\right)^{\mathrm{2}} +\left(\mathrm{2}−\mathrm{2}\right)^{\mathrm{2}} }{\mathrm{5}} \\ $$$${Variance}=\mathrm{0} \\ $$

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