Question Number 163968 by mathls last updated on 12/Jan/22
$$\left(−\mathrm{2}^{\mathrm{2}} \right)^{\mathrm{3}} =? \\ $$
Answered by cortano1 last updated on 12/Jan/22
$$\left(−\mathrm{2}^{\mathrm{2}} \right)=−\mathrm{4} \\ $$$$\left(−\mathrm{2}^{\mathrm{2}} \right)^{\mathrm{3}} =\left(−\mathrm{4}\right)^{\mathrm{3}} =−\mathrm{64} \\ $$
Commented by mathls last updated on 12/Jan/22
$$\left(−\mathrm{2}^{\mathrm{2}} \right)^{\mathrm{3}} =\left(−\mathrm{2}\right)^{\mathrm{6}} =\mathrm{64}\:\:\:{isn}'{t}\:{correct}? \\ $$
Commented by cortano1 last updated on 12/Jan/22
$${no} \\ $$
Commented by cortano1 last updated on 12/Jan/22
$$\left(−\mathrm{2}^{\mathrm{2}} \right)^{\mathrm{3}} =\left(−\mathrm{2}^{\mathrm{2}} \right)×\left(−\mathrm{2}^{\mathrm{2}} \right)×\left(−\mathrm{2}^{\mathrm{2}} \right) \\ $$$$\:=\:\left(−\mathrm{4}\right)×\left(−\mathrm{4}\right)×\left(−\mathrm{4}\right)=−\mathrm{64} \\ $$