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2-30-2-31-




Question Number 43684 by rajesh123456 last updated on 14/Sep/18
2^(30) /2^(31)
$$\mathrm{2}^{\mathrm{30}} /\mathrm{2}^{\mathrm{31}} \\ $$
Commented by Joel578 last updated on 14/Sep/18
(2^p /2^q ) = 2^(p−q)
$$\frac{\mathrm{2}^{{p}} }{\mathrm{2}^{{q}} }\:=\:\mathrm{2}^{{p}−{q}} \\ $$

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