Question Number 26218 by Absa raj last updated on 22/Dec/17
$$\underset{\mathrm{2}} {\overset{\mathrm{4}} {\int}}\mathrm{sin}\theta\:{d}\theta \\ $$
Commented by abdo imad last updated on 22/Dec/17
$$\int_{\mathrm{2}} ^{\mathrm{4}} \:{sin}\theta\:{d}\theta\:=\left[\:−{cos}\theta\:\right]_{\theta=\mathrm{2}} ^{\theta=\mathrm{4}} \:\:={cos}\left(\mathrm{2}\right)\:−{cos}\left(\mathrm{4}\right) \\ $$
Commented by Absa raj last updated on 22/Dec/17
Tnx