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2-i-1-2i-




Question Number 38562 by shakirhsp@gmail.com last updated on 27/Jun/18
((√2) +i)(1−(√(2i)) )
$$\left(\sqrt{\mathrm{2}}\:+{i}\right)\left(\mathrm{1}−\sqrt{\mathrm{2}{i}}\:\right) \\ $$
Answered by MJS last updated on 27/Jun/18
((√2)+i)(1−(√(2i)))=((√2)+i)(1−(1+i))=  =((√2)+i)(−i)=1−i(√2)  ((√2)+i)(1−(√2)i)=(√2)−2i+i+(√2)=2(√2)−i
$$\left(\sqrt{\mathrm{2}}+\mathrm{i}\right)\left(\mathrm{1}−\sqrt{\mathrm{2i}}\right)=\left(\sqrt{\mathrm{2}}+\mathrm{i}\right)\left(\mathrm{1}−\left(\mathrm{1}+\mathrm{i}\right)\right)= \\ $$$$=\left(\sqrt{\mathrm{2}}+\mathrm{i}\right)\left(−\mathrm{i}\right)=\mathrm{1}−\mathrm{i}\sqrt{\mathrm{2}} \\ $$$$\left(\sqrt{\mathrm{2}}+\mathrm{i}\right)\left(\mathrm{1}−\sqrt{\mathrm{2}}\mathrm{i}\right)=\sqrt{\mathrm{2}}−\mathrm{2i}+\mathrm{i}+\sqrt{\mathrm{2}}=\mathrm{2}\sqrt{\mathrm{2}}−\mathrm{i} \\ $$
Commented by shakirhsp@gmail.com last updated on 04/Jul/18
      thanks brother
$$ \\ $$$$ \\ $$$$ \\ $$$$\mathrm{thanks}\:\mathrm{brother} \\ $$$$ \\ $$

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