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2-k-1-3-k-2-0-mod-k-5-min-k-k-N-

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Question Number 146130 by Huy last updated on 11/Jul/21
(2^k +1)(3^k +2)≡0(mod k+5) min k=? (k∈N)
(2k+1)(3k+2)≡0(modk+5)mink=?(k∈N)

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