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2-x-2-3-dx-




Question Number 84957 by john santu last updated on 17/Mar/20
∫ (2−x^2 )^3  dx =
$$\int\:\left(\mathrm{2}−\mathrm{x}^{\mathrm{2}} \right)^{\mathrm{3}} \:\mathrm{dx}\:=\: \\ $$
Commented by john santu last updated on 17/Mar/20
∫ (8−3(4x^2 )+3(2x^4 )−x^6 ) dx =   ∫ (8−12x^2 +6x^4 −x^6 ) dx =   8x − 4x^3 +(6/5)x^5 −(1/7)x^7  +c
$$\int\:\left(\mathrm{8}−\mathrm{3}\left(\mathrm{4x}^{\mathrm{2}} \right)+\mathrm{3}\left(\mathrm{2x}^{\mathrm{4}} \right)−\mathrm{x}^{\mathrm{6}} \right)\:\mathrm{dx}\:=\: \\ $$$$\int\:\left(\mathrm{8}−\mathrm{12x}^{\mathrm{2}} +\mathrm{6x}^{\mathrm{4}} −\mathrm{x}^{\mathrm{6}} \right)\:\mathrm{dx}\:=\: \\ $$$$\mathrm{8x}\:−\:\mathrm{4x}^{\mathrm{3}} +\frac{\mathrm{6}}{\mathrm{5}}\mathrm{x}^{\mathrm{5}} −\frac{\mathrm{1}}{\mathrm{7}}\mathrm{x}^{\mathrm{7}} \:+\mathrm{c}\: \\ $$$$ \\ $$

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