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2-x-2-x-2-solve-for-x-

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Question Number 170781 by solomonwells last updated on 30/May/22
(√((2−x))) = (2−x)^2 solve for x
(2−x)=(2−x)2solveforx
Answered by Rasheed.Sindhi last updated on 30/May/22
(((2−x)^2 )/((2−x)^(1/2) ))=1 (2−x)^(3/2) =1^(3/2) 2−x=1 x=1
(2−x)2(2−x)1/2=1(2−x)3/2=13/22−x=1x=1
Commented by mr W last updated on 30/May/22
x=2 is also good
x=2isalsogood
Commented by Rasheed.Sindhi last updated on 30/May/22
Of course sir: (√(2−x)) =(2−x)^2 (√(2−x)) −(2−x)^2 =0 (√(2−x)) (1−(2−x)^(3/2) )=0 (√(2−x)) =0 ∣ (2−x)^(3/2) =1 x=2 ∣ (2−x)^(3/2) =1^(3/2) 2−x=1 x=1
Ofcoursesir:2−x=(2−x)22−x−(2−x)2=02−x(1−(2−x)3/2)=02−x=0∣(2−x)3/2=1x=2∣(2−x)3/2=13/22−x=1x=1
Answered by MJS_new last updated on 31/May/22
t=(√(2−x)) ≥0 ⇔ x=2−t^2 t=t^4 t(t^3 −1)=0 t=0∨t=1 ⇒ x=1∨x=2
t=2−x⩾0⇔x=2−t2t=t4t(t3−1)=0t=0∨t=1⇒x=1∨x=2

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