2-x-3-2-x-3-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 82577 by M±th+et£s last updated on 22/Feb/20 ∫2−x+32+x−3dx Commented by mathmax by abdo last updated on 22/Feb/20 letI=∫2−x+32+x+3dxvhangement2+x+3=tgivex+3=t−2⇒x+3=(t−2)2=t2−4t+4⇒x=t2−4t+1⇒I=∫2−t2−4t+1+3t(2t−4)dt=2∫(t−2)t2−4t+4tdt=2∫(t−2)(t−2)tdt=2∫t2−4t+4tdt=2∫(t−4+4t)dt=t2−8t+8ln∣t∣+C=(2+x+3)2−8(2+x+3)+8ln∣2+x+3∣+C Commented by M±th+et£s last updated on 22/Feb/20 godblessyousir Commented by msup trace by abdo last updated on 22/Feb/20 thankyousir. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-82574Next Next post: Question-148112 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.