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2-x-3-y-2-1-

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Question Number 53007 by Tristan last updated on 16/Jan/19
2^x ×3−y^2 =−1
$$\mathrm{2}^{\mathrm{x}} ×\mathrm{3}−\mathrm{y}^{\mathrm{2}} =−\mathrm{1} \\ $$

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