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2-x-4-2x-2-3-y-4-3y-2-4-7-Find-x-y-




Question Number 48204 by ajfour last updated on 20/Nov/18
2(x^4 −2x^2 +3)(y^4 −3y^2 +4)=7  Find (x,y) .
2(x42x2+3)(y43y2+4)=7Find(x,y).
Answered by ajfour last updated on 20/Nov/18
2[(x^2 −1)^2 +2][(y^2 −(3/2))^2 +(7/4)]= 7  ⇒  x = ±1,  y = ±(√(3/2))       four points.
2[(x21)2+2][(y232)2+74]=7x=±1,y=±32fourpoints.

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