Question Number 52653 by abdullahnewton last updated on 10/Jan/19
$$\mathrm{2}\:{X}\:\:+\:\:\mathrm{5}\:^{\mathrm{2}\:} \:\:=\:\:\:\:\sqrt{\mathrm{9}}\:\:\:\:−\:\:\:{X} \\ $$$$\mathrm{2}\:\:{X}\:\:\:+\:\:\:{X}\:\:\:=\:\:\:\mathrm{3}\:\:\:−\:\:\:\mathrm{25} \\ $$$$\mathrm{3}\:\:{X}\:\:\:=\:\:\:−\:\mathrm{22} \\ $$$${X}\:\:=\:\:\frac{\mathrm{22}}{\mathrm{3}} \\ $$$$ \\ $$$$\mathrm{6}\:{Z}\:\:−\:\mathrm{63}\:\:=\:\:\mathrm{1}\:\:−\:\:\mid\:\:\:−\:\:\mathrm{20}\:\:\mid \\ $$$$\mathrm{6}\:{Z}\:\:=\:\:\mathrm{1}\:\:−\:\:\mathrm{20}\:\:+\:\:\mathrm{63} \\ $$$$\mathrm{6}\:\:{Z}\:\:=\:\:\mathrm{44} \\ $$$${Z}\:\:=\:\:\frac{\mathrm{44}}{\mathrm{6}}\:\:=\:\:\frac{\mathrm{22}}{\mathrm{3}}\:\:\:\:\:\because\:{s}\left({x}\right)={s}\left({z}\right),\therefore{X}={Z} \\ $$