Question Number 185414 by Safiullah_21 last updated on 21/Jan/23
$$\mathrm{2}^{{x}} ={a} \\ $$$$\mathrm{3}^{{y}} ={b}\:\:\:\:\:\::\:\mathrm{6}^{{xy}} =? \\ $$$$\Rightarrow\mathrm{6}^{{xy}} =\left(\mathrm{2}×\mathrm{3}\right)^{{xy}} \Rightarrow\mathrm{2}^{{xy}} ×\mathrm{3}^{{xy}} \Rightarrow\left(\mathrm{2}^{{x}} \right)^{{y}} ×\left(\mathrm{3}^{{y}} \right)^{{x}} \Rightarrow{a}^{{y}} ×{b}^{{x}} \\ $$
Commented by mr W last updated on 21/Jan/23
$${is}\:{a}^{{y}} {b}^{{x}} \:{better}\:{than}\:\mathrm{6}^{{xy}} \:? \\ $$