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2-Z-1-a-1-b-Z-help-




Question Number 167722 by SAMIRA last updated on 23/Mar/22
(2/Z) = (1/a)+(1/b)  Z = ??? help
$$\frac{\mathrm{2}}{\boldsymbol{\mathrm{Z}}}\:=\:\frac{\mathrm{1}}{\boldsymbol{\mathrm{a}}}+\frac{\mathrm{1}}{\boldsymbol{\mathrm{b}}} \\ $$$$\boldsymbol{\mathrm{Z}}\:=\:???\:{help} \\ $$
Commented by MJS_new last updated on 23/Mar/22
law of adding fractions  (o/p)+(q/r)=((o×r)/(p×r))+((p×q)/(p×r))=((o×r+p×q)/(p×r))  (2/Z)=(1/a)+(1/b)  (2/Z)=((a+b)/(a×b))  (Z/2)=((a×b)/(a+b))  Z=((2×a×b)/(a+b))
$$\mathrm{law}\:\mathrm{of}\:\mathrm{adding}\:\mathrm{fractions} \\ $$$$\frac{{o}}{{p}}+\frac{{q}}{{r}}=\frac{{o}×{r}}{{p}×{r}}+\frac{{p}×{q}}{{p}×{r}}=\frac{{o}×{r}+{p}×{q}}{{p}×{r}} \\ $$$$\frac{\mathrm{2}}{{Z}}=\frac{\mathrm{1}}{{a}}+\frac{\mathrm{1}}{{b}} \\ $$$$\frac{\mathrm{2}}{{Z}}=\frac{{a}+{b}}{{a}×{b}} \\ $$$$\frac{{Z}}{\mathrm{2}}=\frac{{a}×{b}}{{a}+{b}} \\ $$$${Z}=\frac{\mathrm{2}×{a}×{b}}{{a}+{b}} \\ $$
Answered by pnuvu last updated on 23/Mar/22
Z=((2ab)/(a+b))
$$\boldsymbol{{Z}}=\frac{\mathrm{2}{ab}}{{a}+{b}} \\ $$

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