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2014-x-3-4029x-2-2-0-x-1-lt-x-2-lt-x-3-x-2-x-1-x-3-

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Question Number 64124 by ANTARES VY last updated on 13/Jul/19
(√(2014))x^3 −4029x^2 +2=0 x_1 <x_2 <x_3 x_2 (x_1 +x_3 )=?
2014x3−4029x2+2=0x1<x2<x3x2(x1+x3)=?

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