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24-2x-1-3-dx-




Question Number 164684 by Zaynal last updated on 20/Jan/22
∫24(2x−1)^(−3)  dx
$$\int\mathrm{24}\left(\mathrm{2}\boldsymbol{{x}}−\mathrm{1}\right)^{−\mathrm{3}} \:\boldsymbol{{dx}} \\ $$
Answered by Ar Brandon last updated on 20/Jan/22
=∫((24)/((2x−1)^3 ))dx=−(6/((2x−1)^2 ))+C
$$=\int\frac{\mathrm{24}}{\left(\mathrm{2}{x}−\mathrm{1}\right)^{\mathrm{3}} }{dx}=−\frac{\mathrm{6}}{\left(\mathrm{2}{x}−\mathrm{1}\right)^{\mathrm{2}} }+{C} \\ $$

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