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24-log-10-x-26-log-10-x-1-x-




Question Number 153681 by EDWIN88 last updated on 09/Sep/21
  24^(log _(10) (x)) −26^(log _(10) (x)) =1   x=?
$$\:\:\mathrm{24}^{\mathrm{log}\:_{\mathrm{10}} \left({x}\right)} −\mathrm{26}^{\mathrm{log}\:_{\mathrm{10}} \left({x}\right)} =\mathrm{1} \\ $$$$\:{x}=? \\ $$
Answered by MJS_new last updated on 09/Sep/21
no solution in C
$$\mathrm{no}\:\mathrm{solution}\:\mathrm{in}\:\mathbb{C} \\ $$

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