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27x-2-3x-2-dx-




Question Number 164682 by Zaynal last updated on 20/Jan/22
∫27x^2  (√(3x−2)) dx
$$\int\mathrm{27}\boldsymbol{{x}}^{\mathrm{2}} \:\sqrt{\mathrm{3}\boldsymbol{{x}}−\mathrm{2}}\:\boldsymbol{{dx}} \\ $$
Answered by Ar Brandon last updated on 20/Jan/22
=3∫(3x−2+2)^2 (√(3x−2))dx  =3∫((3x−2)^(5/2) +4(3x−2)^(3/2) +4(3x−2)^(1/2) )dx
$$=\mathrm{3}\int\left(\mathrm{3}{x}−\mathrm{2}+\mathrm{2}\right)^{\mathrm{2}} \sqrt{\mathrm{3}{x}−\mathrm{2}}{dx} \\ $$$$=\mathrm{3}\int\left(\left(\mathrm{3}{x}−\mathrm{2}\right)^{\frac{\mathrm{5}}{\mathrm{2}}} +\mathrm{4}\left(\mathrm{3}{x}−\mathrm{2}\right)^{\frac{\mathrm{3}}{\mathrm{2}}} +\mathrm{4}\left(\mathrm{3}{x}−\mathrm{2}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right){dx} \\ $$

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