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2cos-pi-3-cos-9pi-13-cos-3pi-13-cos-5pi-13-0-




Question Number 20884 by tammi last updated on 06/Sep/17
2cos (π/3)cos ((9π)/(13))+cos ((3π)/(13))+cos ((5π)/(13))=0
2cosπ3cos9π13+cos3π13+cos5π13=0
Answered by ajfour last updated on 06/Sep/17
must start with    2cos (π/(13))..., Then   L.H.S. = cos (((10π)/(13)))+cos (((8π)/(13)))+                                 cos (((3π)/(13)))+cos (((5π)/(13)))         =cos (π−((3π)/(13)))+cos (π−((5π)/(13)))                +cos (((3π)/(13)))+cos (((5π)/(13)))     =−cos (((3π)/(13)))−cos (((5π)/(13)))+cos (((3π)/(13)))                               +cos (((5π)/(13))) = 0 .
muststartwith2cosπ13,ThenL.H.S.=cos(10π13)+cos(8π13)+cos(3π13)+cos(5π13)=cos(π3π13)+cos(π5π13)+cos(3π13)+cos(5π13)=cos(3π13)cos(5π13)+cos(3π13)+cos(5π13)=0.

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