2cos-pi-3-cos-9pi-13-cos-3pi-13-cos-5pi-13-0- Tinku Tara June 4, 2023 Trigonometry 0 Comments FacebookTweetPin Question Number 20884 by tammi last updated on 06/Sep/17 2cosπ3cos9π13+cos3π13+cos5π13=0 Answered by ajfour last updated on 06/Sep/17 muststartwith2cosπ13…,ThenL.H.S.=cos(10π13)+cos(8π13)+cos(3π13)+cos(5π13)=cos(π−3π13)+cos(π−5π13)+cos(3π13)+cos(5π13)=−cos(3π13)−cos(5π13)+cos(3π13)+cos(5π13)=0. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 8-68-Next Next post: f-x-a-x-1-x-D-f-0-a-1-h-x-f-1-a-ax-f-1-a-2x-D-h-D-Domain- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.