2F1-1-2-1-2-1-2-z-1-z-1-2-1-by-kummer-transformation-2F1-1-2-1-2-1-2-z-2F1-1-2-1-2-1-1-2-1-2-1-2-z-2F1-1-2-1-2-1-2-z-sin-1-1-z-1-z-2-why-do-i-g

Question Number 97476 by M±th+et+s last updated on 08/Jun/20

2 F 1 (\frac{1}{2}, \frac{1}{2}; \frac{1}{2}; z) = {(1 - z)}^{\frac{1}{2}} * * 1

b y k u m m e r t r a n s f o r m a t i o n

2 F 1 (\frac{1}{2}, \frac{1}{2}; \frac{1}{2}; z) = 2 F 1 (\frac{1}{2}, \frac{1}{2}; 1 + \frac{1}{2} + \frac{1}{2} - \frac{1}{2}; z)

2 F 1 (\frac{1}{2}, \frac{1}{2}; \frac{1}{2}; z) = \frac{{s i n}^{- 1} \sqrt{1 - z}}{\sqrt{1 - z}} * * 2

w h y d o i g e t d i f f e r e n t a n s w e r i n

* * 1 a n d 2 * *