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2tanx-1-1-2tanx-1-1-tanx-2-2-1-




Question Number 114656 by vylollloll last updated on 20/Sep/20
2tanx−1=1  ⇔2tanx=1+1  tanx=(2/2)=1
$$\mathrm{2}{tanx}−\mathrm{1}=\mathrm{1} \\ $$$$\Leftrightarrow\mathrm{2}{tanx}=\mathrm{1}+\mathrm{1} \\ $$$${tanx}=\frac{\mathrm{2}}{\mathrm{2}}=\mathrm{1} \\ $$
Commented by vylollloll last updated on 20/Sep/20
Commented by bobhans last updated on 20/Sep/20
5cot 10x−1000=1000  5cot 10x = 1000+1000  5cot 10x=2000⇒cot 10x=((2000)/5)=400
$$\mathrm{5cot}\:\mathrm{10}{x}−\mathrm{1000}=\mathrm{1000} \\ $$$$\mathrm{5cot}\:\mathrm{10}{x}\:=\:\mathrm{1000}+\mathrm{1000} \\ $$$$\mathrm{5cot}\:\mathrm{10}{x}=\mathrm{2000}\Rightarrow\mathrm{cot}\:\mathrm{10}{x}=\frac{\mathrm{2000}}{\mathrm{5}}=\mathrm{400} \\ $$
Answered by 1549442205PVT last updated on 20/Sep/20
tanx=1⇔x=(π/4)+kπ
$$\mathrm{tanx}=\mathrm{1}\Leftrightarrow\mathrm{x}=\frac{\pi}{\mathrm{4}}+\mathrm{k}\pi \\ $$

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