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2x-2x-3-9-0-if-there-s-a-solution-to-equation-find-4a-3-




Question Number 147011 by mathdanisur last updated on 17/Jul/21
2x - (√(2x - 3)) - 9 = 0  if there′s a solution to equation,  find  4a + 3 = ?
2x2x39=0iftheresasolutiontoequation,find4a+3=?
Commented by 7770 last updated on 17/Jul/21
 4x^2 −36x+81−2x+3=0   4x^2 −38x+84=0   x_1 =6      x_2 =3.5   ∴ 4(3.5)+3=17       4(6)+3=27
4x236x+812x+3=04x238x+84=0x1=6x2=3.54(3.5)+3=174(6)+3=27
Commented by otchereabdullai@gmail.com last updated on 18/Jul/21
nice question
nicequestion
Commented by mathdanisur last updated on 18/Jul/21
thank you Ser
thankyouSer
Answered by gsk2684 last updated on 17/Jul/21
((√(2a−3)))^2 −(√(2a−3))−6=0  t^2 −t−6=0  (t−3)(t+2)=0  t=3   (√(2a−3))=3  2a=12  4a+3=27
(2a3)22a36=0t2t6=0(t3)(t+2)=0t=32a3=32a=124a+3=27
Commented by mathdanisur last updated on 17/Jul/21
thankyou Ser, but answer 17
thankyouSer,butanswer17
Commented by gsk2684 last updated on 17/Jul/21
if so then a=((17−3)/4)=((14)/4)=(7/2)  2a−(√(2a−3))−9  7−2−9  ≠0
ifsothena=1734=144=722a2a397290
Commented by mathdanisur last updated on 18/Jul/21
thank you Ser
thankyouSer
Answered by Rasheed.Sindhi last updated on 17/Jul/21
2x - (√(2x - 3)) - 9 = 0                   4a+3=? a: solution to the equation_(−)   4x^2 −36x+81=2x−3  4x^2 −38x+84=0  2x^2 −19x+42=0  (x−6)(2x−7)=0  x=6 ∨ x=7/2 (Extaneous root)  a=6  4a+3=4(6)+3=27  ( If x=7/2 were satisfied   then 4a+3=4((7/2))+3=17 )
2x2x39=04a+3=?a:solutiontotheequation4x236x+81=2x34x238x+84=02x219x+42=0(x6)(2x7)=0x=6x=7/2(Extaneousroot)a=64a+3=4(6)+3=27(Ifx=7/2weresatisfiedthen4a+3=4(72)+3=17)
Commented by mathdanisur last updated on 17/Jul/21
thank you Ser
thankyouSer
Commented by mathdanisur last updated on 18/Jul/21
thank you Ser
thankyouSer

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