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2x-3y-4z-1-min-1-x-1-y-1-z-




Question Number 115888 by Fikret last updated on 29/Sep/20
2x+3y+4z=1  ⇒min((1/x)+(1/y)+(1/z))
2x+3y+4z=1min(1x+1y+1z)
Commented by mr W last updated on 29/Sep/20
let 3y+4z→1  ⇒2x+1→1  ⇒x→0  ((1/x)+(1/y)+(1/z))→∞ or −∞  ⇒no maximum or minimum !
let3y+4z12x+11x0(1x+1y+1z)ornomaximumorminimum!

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