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2xy-2-y-dx-2x-x-2-y-dy-




Question Number 92452 by jagoll last updated on 07/May/20
(2xy^2 −y)dx = (2x−x^2 y)dy
$$\left(\mathrm{2xy}^{\mathrm{2}} −\mathrm{y}\right)\mathrm{dx}\:=\:\left(\mathrm{2x}−\mathrm{x}^{\mathrm{2}} \mathrm{y}\right)\mathrm{dy}\: \\ $$

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