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Question Number 109954 by Study last updated on 26/Aug/20
!3=????
!3=????
Answered by mathdave last updated on 26/Aug/20
solution  recall that  !x=x!Σ_(n=0) ^x (((−1)^n )/(n!))  !3=3!Σ_(n=0) ^3 (((−1)^n )/(n!))=6((((−1)^0 )/(0!))+(((−1)^1 )/(1!))+(((−1)^2 )/(2!))+(((−1)^3 )/(3!)))  !3=6(1−1+(1/2)−(1/6))=6(((3−1)/6))=2  ∵  !3=2   this mean that the how many way 3  object can be disarrange is 2ways
solutionrecallthat!x=x!xn=0(1)nn!!3=3!3n=0(1)nn!=6((1)00!+(1)11!+(1)22!+(1)33!)!3=6(11+1216)=6(316)=2!3=2thismeanthatthehowmanyway3objectcanbedisarrangeis2ways
Commented by mathdave last updated on 26/Aug/20
i mean that 3  object can be  disarrage in  2ways
imeanthat3objectcanbedisarragein2ways

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