3-2-2-i-1-5-

Question Number 35478 by 7991 last updated on 19/May/18

\sqrt[5]{3 \sqrt{2} (2 - i)} = \dots ? ?

Commented by MJS last updated on 19/May/18

these are all the same

z = a + b i = r e^{φ i} = r \cos (φ) + r \sin (φ) i

z^{\frac{p}{q}} = r^{\frac{p}{q}} e^{\frac{q φ}{p} i} = r^{\frac{p}{q}} \cos (\frac{q φ}{p}) + r^{\frac{p}{q}} \sin (\frac{q φ}{p}) i

Facebook Tweet Pin