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3-9x-2-5-25x-2-5-125x-3-1-x-2-




Question Number 99737 by bemath last updated on 23/Jun/20
((3−9x^2 )/(5−25x^2 )) = ((5−125x^3 )/(1−x^2 ))
$$\frac{\mathrm{3}−\mathrm{9x}^{\mathrm{2}} }{\mathrm{5}−\mathrm{25x}^{\mathrm{2}} }\:=\:\frac{\mathrm{5}−\mathrm{125x}^{\mathrm{3}} }{\mathrm{1}−\mathrm{x}^{\mathrm{2}} } \\ $$

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