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Question Number 92489 by ajfour last updated on 07/May/20

(3 + \frac{c q}{12 b}) s^{2} + \frac{6 c}{b} s + (\frac{8 c^{2}}{3 b^{2}} - b) = 0

(1 + \frac{c q}{4 b}) s^{2} + \frac{3 c}{b} (1 - \frac{c q}{12 b}) s + (\frac{12 c^{2}}{b^{2}} - b) = 0

s o l v e s i m u l t a n e o u s l y f o r q a n d s

i n t e r m s o f b a n d c .