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3-cq-12b-s-2-6c-b-s-8c-2-3b-2-b-0-1-cq-4b-s-2-3c-b-1-cq-12b-s-12c-2-b-2-b-0-solve-simultaneously-for-q-and-s-in-terms-of-b-and-c-




Question Number 92489 by ajfour last updated on 07/May/20
(3+((cq)/(12b)))s^2 +((6c)/b)s+(((8c^2 )/(3b^2 ))−b)=0  (1+((cq)/(4b)))s^2 +((3c)/b)(1−((cq)/(12b)))s+(((12c^2 )/b^2 )−b)=0  solve simultaneously for q and s  in terms of b and c.
$$\left(\mathrm{3}+\frac{{cq}}{\mathrm{12}{b}}\right){s}^{\mathrm{2}} +\frac{\mathrm{6}{c}}{{b}}{s}+\left(\frac{\mathrm{8}{c}^{\mathrm{2}} }{\mathrm{3}{b}^{\mathrm{2}} }−{b}\right)=\mathrm{0} \\ $$$$\left(\mathrm{1}+\frac{{cq}}{\mathrm{4}{b}}\right){s}^{\mathrm{2}} +\frac{\mathrm{3}{c}}{{b}}\left(\mathrm{1}−\frac{{cq}}{\mathrm{12}{b}}\right){s}+\left(\frac{\mathrm{12}{c}^{\mathrm{2}} }{{b}^{\mathrm{2}} }−{b}\right)=\mathrm{0} \\ $$$${solve}\:{simultaneously}\:{for}\:\boldsymbol{{q}}\:{and}\:\boldsymbol{{s}} \\ $$$${in}\:{terms}\:{of}\:{b}\:{and}\:{c}. \\ $$

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