3-log-3-2-log-3-3log-1-3-cot-pi-3-log-pi-3-log-2-pi-

Question Number 95968 by i jagooll last updated on 29/May/20

3^{\frac{\log_{3} (2) + \log_{3} (3 \log_{\frac{1}{3}} (\cot \frac{π}{3}))}{\log_{π} (3) . (\log_{2} (π))} ?}

Answered by john santu last updated on 29/May/20

\Rightarrow \log_{3} (2) + \log_{3} (3 \log_{3} (\tan (\frac{π}{3})) =

\log_{3} (2) + \log_{3} (3 \log_{3} (\sqrt{3})) =

\log_{3} (2 \times \frac{3}{2}) = 1

\Rightarrow \frac{1}{\log_{π} (3) . \log_{2} (π)} = \frac{1}{\log_{2} (3)}

so 3^{\log_{3} (2)} = 2 .

Commented by 1549442205 last updated on 29/May/20

your answer is false, numerator equal

to 1!

Commented by 1549442205 last updated on 29/May/20

\log_{3} (2) + \log_{3} ({3 \log}_{\frac{1}{3}} (\cot \frac{π}{3})) =

\log_{3} (2) + \log_{3} ({3 \log}_{\frac{1}{3}} {(\frac{1}{3})}^{\frac{1}{2}}) = \log_{3} (2) +

\log_{3} (3 . \frac{1}{2}) = \log_{3} (2) + lo \underset{3}{g 3} - \log_{3} (2) = 1

Commented by i jagooll last updated on 29/May/20

yes \dots thank you