30cm-3-of-hydrogen-at-s-t-p-combines-with-20cm-3-of-oxygen-to-form-steam-according-to-the-following-equation-2H-2-g-O-2-g-2H-2-O-g-Calculate-the-total-volume-of-gaseous-mixture-at-th

Question Number 18429 by tawa tawa last updated on 21/Jul/17

{30 cm}^{3} of hydrogen at s . t . p combines with {20 cm}^{3} of oxygen to form steam

according to the following equation, {2 H}_{2} (g) + O_{2} (g) \to {2 H}_{2} O (g) .

Calculate the total volume of gaseous mixture at the end of the reaction .

Commented by tawa tawa last updated on 21/Jul/17

Please help with workings

Commented by tawa tawa last updated on 21/Jul/17

I {don}^{'} t know it sir

Commented by tawa tawa last updated on 21/Jul/17

Help me with the way you think it should be . God bless you sir .

Commented by Tinkutara last updated on 21/Jul/17

1 {cm}^{3} of O_{2} requires 2 {cm}^{3} of H_{2} .

∴ 20 {cm}^{3} of O_{2} requires 40 {cm}^{3} of H_{2} .

But available H_{2} is only 30 {cm}^{3} . Hence

it is the limiting reagent .

Now 2 {cm}^{3} of H_{2} produces 2 {cm}^{3} of H_{2} O .

∴ 30 {cm}^{3} of H_{2} produces 30 {cm}^{3} of H_{2} O .

Volume of O_{2} left unreacted = 5 {cm}^{3}

Hence final volume after the reaction

of is 35 {cm}^{3} .

Commented by tawa tawa last updated on 21/Jul/17

God bless you sir .

Commented by tawa tawa last updated on 23/Jul/17

The answer is correct sir .