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36x-2-2x-3-7-dx-




Question Number 164686 by Zaynal last updated on 20/Jan/22
∫36x^2  (2x+3)^(−7)  dx
$$\int\mathrm{36}\boldsymbol{{x}}^{\mathrm{2}} \:\left(\mathrm{2}\boldsymbol{{x}}+\mathrm{3}\right)^{−\mathrm{7}} \:\boldsymbol{{dx}} \\ $$$$\: \\ $$
Answered by Ar Brandon last updated on 20/Jan/22
=36∫(x^2 /((2x+3)^7 ))dx=9∫(((2x+3−3)^2 )/((2x+3)^7 ))dx  =9∫((1/((2x+3)^5 ))−(6/((2x+3)^6 ))+(9/((2x+3)^7 )))dx
$$=\mathrm{36}\int\frac{{x}^{\mathrm{2}} }{\left(\mathrm{2}{x}+\mathrm{3}\right)^{\mathrm{7}} }{dx}=\mathrm{9}\int\frac{\left(\mathrm{2}{x}+\mathrm{3}−\mathrm{3}\right)^{\mathrm{2}} }{\left(\mathrm{2}{x}+\mathrm{3}\right)^{\mathrm{7}} }{dx} \\ $$$$=\mathrm{9}\int\left(\frac{\mathrm{1}}{\left(\mathrm{2}{x}+\mathrm{3}\right)^{\mathrm{5}} }−\frac{\mathrm{6}}{\left(\mathrm{2}{x}+\mathrm{3}\right)^{\mathrm{6}} }+\frac{\mathrm{9}}{\left(\mathrm{2}{x}+\mathrm{3}\right)^{\mathrm{7}} }\right){dx} \\ $$

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