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3a-2-b-3-c-5b-4-c-6xy-3-z-16-10x-2-y-2-z-10-Can-you-solve-this-




Question Number 104297 by Anindita last updated on 20/Jul/20
((3a^2 b^3 c)/(5b^4 c))+((6xy^3 z^(16) )/(10x^2 y^2 z^(10) )) = ?  Can you solve this?
$$\frac{\mathrm{3}{a}^{\mathrm{2}} {b}^{\mathrm{3}} {c}}{\mathrm{5}{b}^{\mathrm{4}} {c}}+\frac{\mathrm{6}{xy}^{\mathrm{3}} {z}^{\mathrm{16}} }{\mathrm{10}{x}^{\mathrm{2}} {y}^{\mathrm{2}} {z}^{\mathrm{10}} }\:=\:? \\ $$$$\boldsymbol{\mathrm{Can}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}? \\ $$
Answered by bemath last updated on 20/Jul/20
((3a^2 )/(5b)) + ((3yz^6 )/(5x)) = (3/5)[(a^2 /b)+((yz^6 )/x)]  =(3/5)[((a^2 x+byz^6 )/(bx))]
$$\frac{\mathrm{3}{a}^{\mathrm{2}} }{\mathrm{5}{b}}\:+\:\frac{\mathrm{3}{yz}^{\mathrm{6}} }{\mathrm{5}{x}}\:=\:\frac{\mathrm{3}}{\mathrm{5}}\left[\frac{{a}^{\mathrm{2}} }{{b}}+\frac{{yz}^{\mathrm{6}} }{{x}}\right] \\ $$$$=\frac{\mathrm{3}}{\mathrm{5}}\left[\frac{{a}^{\mathrm{2}} {x}+{byz}^{\mathrm{6}} }{{bx}}\right] \\ $$

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