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3x-4-4x-3-7x-2-4x-5-0-x-




Question Number 58046 by ANTARES VY last updated on 17/Apr/19
3x^4 −4x^3 −7x^2 −4x+5=0  x=?
3x44x37x24x+5=0x=?
Answered by tanmay last updated on 17/Apr/19
f(x)=3x^4 −4x^3 −7x^2 −4x+5  f(0)=5         so    f(0)>0  f(1)=−7              f(1)<0  since f(0)>0 and f(1)<0  so one root lies between  (0,1)←look here    f(2)=48−32−28−8+5          =53−68=−15  since f(1)<0  and f(2)<0   so no root between (1,2)←look here    f(3)=243−108−28−8+5            =248−144            =104  f(3)>0  since f(2)<0   and f(3)>0  so one root between  (2,3)←look here  f(4)=389   f(4)>0  since f(3)>0  and f(4)>0  so no root between (3,4)  i have tried to find the location of roots..
f(x)=3x44x37x24x+5f(0)=5sof(0)>0f(1)=7f(1)<0sincef(0)>0andf(1)<0soonerootliesbetween(0,1)lookheref(2)=4832288+5=5368=15sincef(1)<0andf(2)<0sonorootbetween(1,2)lookheref(3)=243108288+5=248144=104f(3)>0sincef(2)<0andf(3)>0soonerootbetween(2,3)lookheref(4)=389f(4)>0sincef(3)>0andf(4)>0sonorootbetween(3,4)ihavetriedtofindthelocationofroots..
Answered by MJS last updated on 17/Apr/19
x_1 ≈.571581  x_2 ≈2.41140  x_3 ≈−.824822−.727241  x_4 ≈−.824822+.727241
x1.571581x22.41140x3.824822.727241x4.824822+.727241

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