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3x-5-3x-2-10x-2-1-3-dx-Solve-it-without-substitution-method-




Question Number 146689 by naka3546 last updated on 15/Jul/21
∫  ((−3x+5)/( (((3x^2 −10x)^2 ))^(1/3) ))  dx  =   ...  ?  Solve  it  without  substitution  method.
3x+5(3x210x)23dx=?Solveitwithoutsubstitutionmethod.
Answered by Ar Brandon last updated on 15/Jul/21
I=∫((−3x+5)/( (((3x^2 −10x)^2 ))^(1/3) ))dx     =−(1/2)∫((6x−10)/( (((3x^2 −10x)^2 ))^(1/3) ))dx     =−(1/2)∫((d(3x^2 −10x))/( (((3x^2 −10x)^2 ))^(1/3) ))     =−(3/2)((3x^2 −10x))^(1/3) +C
I=3x+5(3x210x)23dx=126x10(3x210x)23dx=12d(3x210x)(3x210x)23=323x210x3+C
Commented by naka3546 last updated on 15/Jul/21
thank you, sir.
thankyou,sir.

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