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3x-sin-1-4x-2-1-16x-4-dx-




Question Number 14431 by tawa tawa last updated on 31/May/17
∫  ((3x sin^(−1) (4x^2 ))/( (√(1 − 16x^4 )))) dx
$$\int\:\:\frac{\mathrm{3x}\:\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{4x}^{\mathrm{2}} \right)}{\:\sqrt{\mathrm{1}\:−\:\mathrm{16x}^{\mathrm{4}} }}\:\mathrm{dx} \\ $$

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