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3xy-2x-2-dy-3x-2-3y-dx-0-

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Question Number 125721 by bramlexs22 last updated on 13/Dec/20
(3xy+2x^2 )dy + (3x^2 +3y)dx=0
$$\:\left(\mathrm{3}{xy}+\mathrm{2}{x}^{\mathrm{2}} \right){dy}\:+\:\left(\mathrm{3}{x}^{\mathrm{2}} +\mathrm{3}{y}\right){dx}=\mathrm{0} \\ $$

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