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4-1-x-6-1-x-9-1-x-x-R-




Question Number 187672 by Humble last updated on 20/Feb/23
4^(−(1/x)) +6^(−(1/x))  = 9^(−(1/x))   x∈R
41x+61x=91xxR
Answered by SEKRET last updated on 20/Feb/23
  (4^(− (1/x)) /9^(− (1/x)) ) + (6^((−1)/x) /9^((−1)/x) ) =1    ((4/9))^((−1)/x) +((6/9))^((−1)/x) =1    ((2/3))^(2∙ ((−1)/x)) + ((2/3))^((−1)/x) =1      t^2 +t=1     t^2 +2∙(1/2)∙t+(1/4)=1+(1/4)    (t+(1/2))^2 = (5/4)   t=  ((−1∓(√5))/2)    ((2/3))^((−1)/x) = (((√(5 ))  −1)/2)  ((−1)/x)= log_(((2/3))) ((((√5) −1)/2))    (1/x) =log_(((3/2))) ((((√5) −1)/2))    x= log_(((((√5) −1)/2))) ((3/2))
41\boldsymbolx91\boldsymbolx+61\boldsymbolx91\boldsymbolx=1(49)1\boldsymbolx+(69)1\boldsymbolx=1(23)21\boldsymbolx+(23)1\boldsymbolx=1\boldsymbolt2+\boldsymbolt=1\boldsymbolt2+212\boldsymbolt+14=1+14(\boldsymbolt+12)2=54\boldsymbolt=152(23)1\boldsymbolx=5121\boldsymbolx=\boldsymbollog(23)(512)1\boldsymbolx=\boldsymbollog(32)(512)\boldsymbolx=\boldsymbollog(512)(32)
Commented by Humble last updated on 20/Feb/23
nice solution,  sir
nicesolution,sir
Answered by Rasheed.Sindhi last updated on 20/Feb/23
4^(−(1/x)) +6^(−(1/x))  = 9^(−(1/x))   ((4/6))^(−1/x) +1=((9/6))^(−1/x)   ((3/2))^(1/x) +1=((2/3))^(1/x)   y+1=(1/y)  ;y≥0  y^2 +y−1=0  y=((−1+(√(1+4)))/2)  log((3/2))^(1/x) =log (((−1+(√5))/2))  ((1/x))log((3/2))=log(−1+(√5) )−log2  x=((log3−log2  )/(log(−1+(√5) )−log2))
41x+61x=91x(46)1/x+1=(96)1/x(32)1/x+1=(23)1/xy+1=1y;y0y2+y1=0y=1+1+42log(32)1/x=log(1+52)(1x)log(32)=log(1+5)log2x=log3log2log(1+5)log2
Commented by Humble last updated on 20/Feb/23
Excellent!!
Excellent!!Excellent!!

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