Question Number 89074 by Alhaji Bai Sama last updated on 15/Apr/20
$$×^{\mathrm{4}} +×^{\mathrm{2}} =\mathrm{1} \\ $$
Commented by john santu last updated on 15/Apr/20
$${x}^{\mathrm{4}} +{x}^{\mathrm{2}} −\mathrm{1}=\mathrm{0} \\ $$$${x}^{\mathrm{2}} \:=\:\frac{−\mathrm{1}\pm\:\sqrt{\mathrm{5}}}{\mathrm{2}} \\ $$$${x}\:=\:\pm\:\sqrt{\frac{−\mathrm{1}\pm\sqrt{\mathrm{5}}}{\mathrm{2}}} \\ $$