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4-2a-b-2-a-b-2-




Question Number 27761 by shiv15031973@gmail.com last updated on 14/Jan/18
4(2a+b)^2 −(a−b)^2
$$\mathrm{4}\left(\mathrm{2a}+\mathrm{b}\right)^{\mathrm{2}} −\left(\mathrm{a}−\mathrm{b}\right)^{\mathrm{2}} \\ $$
Answered by Rasheed.Sindhi last updated on 14/Jan/18
   4(2a+b)^2 −(a−b)^2   =4(4a^2 +4ab+b^2 )−(a^2 −2ab+b^2 )  =16a^2 +16ab+4b^2 −a^2 +2ab−b^2   =15a^2 +17ab+3b^2
$$\:\:\:\mathrm{4}\left(\mathrm{2a}+\mathrm{b}\right)^{\mathrm{2}} −\left(\mathrm{a}−\mathrm{b}\right)^{\mathrm{2}} \\ $$$$=\mathrm{4}\left(\mathrm{4a}^{\mathrm{2}} +\mathrm{4ab}+\mathrm{b}^{\mathrm{2}} \right)−\left(\mathrm{a}^{\mathrm{2}} −\mathrm{2ab}+\mathrm{b}^{\mathrm{2}} \right) \\ $$$$=\mathrm{16a}^{\mathrm{2}} +\mathrm{16ab}+\mathrm{4b}^{\mathrm{2}} −\mathrm{a}^{\mathrm{2}} +\mathrm{2ab}−\mathrm{b}^{\mathrm{2}} \\ $$$$=\mathrm{15a}^{\mathrm{2}} +\mathrm{17ab}+\mathrm{3b}^{\mathrm{2}} \\ $$

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