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Question Number 157074 by amin96 last updated on 19/Oct/21

\sqrt{4 + \sqrt{4^{2} + \sqrt{4^{3} + \sqrt{4^{4} + \dots}}}} = ?

Answered by MJS_new last updated on 19/Oct/21

3

Commented by amin96 last updated on 19/Oct/21

? ? ? ?

Commented by MJS_new last updated on 19/Oct/21

!!!!

Answered by Javokhir last updated on 19/Oct/21

a + 2 = \sqrt{4 + a \sqrt{16 + a \sqrt{64 + a \sqrt{256 + \dots . .}}}}

a = 1 \Leftrightarrow 3 = \sqrt{4 + \sqrt{16 + \sqrt{64 + \sqrt{256 + \dots}}}}

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