Question Number 59547 by hhghg last updated on 11/May/19
$$\mathrm{4}+\mathrm{t}×\mathrm{c}\:\mathrm{t}=\mathrm{3}\:\mathrm{c}=\mathrm{6} \\ $$
Answered by Forkum Michael Choungong last updated on 11/May/19
$$\mathrm{4}\:+\:{t}\:×\:\mathrm{6}{t}=\mathrm{3} \\ $$$$\mathrm{6}{t}^{\mathrm{2}} +\mathrm{1}=\mathrm{0} \\ $$$$\mathrm{6}{t}^{\mathrm{2}} =−\mathrm{1} \\ $$$${t}^{\mathrm{2}} =−\frac{\mathrm{1}}{\mathrm{6}} \\ $$$${t}=\:\frac{{i}}{\mathrm{6}}\:{or}\:−\frac{{i}}{\mathrm{6}} \\ $$