Question Number 86339 by frempongfaustina24@gmail.com last updated on 28/Mar/20
$$\mathrm{4}^{{x}} +\mathrm{6}^{{x}} =\mathrm{9}^{{x}} \\ $$$$ \\ $$$$ \\ $$
Answered by jagoll last updated on 28/Mar/20
$$\left(\frac{\mathrm{2}}{\mathrm{3}}\right)^{\mathrm{2x}} +\left(\frac{\mathrm{2}}{\mathrm{3}}\right)^{\mathrm{x}} =\mathrm{1} \\ $$$$\mathrm{let}\:\left(\frac{\mathrm{2}}{\mathrm{3}}\right)^{\mathrm{x}} \:=\:\mathrm{t} \\ $$$$\mathrm{t}^{\mathrm{2}} +\:\mathrm{t}\:=\:\mathrm{1}\:\Rightarrow\:\mathrm{t}^{\mathrm{2}} +\mathrm{t}â\mathrm{1}=\mathrm{0} \\ $$$$\mathrm{now}\:\mathrm{it}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{solve} \\ $$