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49-log-7-6-log-3-5-log-2-3-log-5-2-




Question Number 122286 by ZiYangLee last updated on 15/Nov/20
(49^(log_7 6) )^(log_3 5^(log_2 3^(log_5 2) ) ) =?
(49log76)log35log23log52=?
Answered by TANMAY PANACEA last updated on 15/Nov/20
  (49^(log_7 ^6 ) )^(log_3 5^(log_(2 ) 3^(log_(5 ) 2) ) )   (49^a )^b^(((ln2)/(ln5))×((ln3)/(ln2)))    (49^a )^b^((ln3)/(ln5))    (49^a )^(((ln5)/(ln3))×((ln3)/(ln5)))   49^a =p  ln_(49) p=a  ((lnp)/(2ln7))=a=((ln6)/(ln7))  lnp=2ln6=ln6^2   p=36
(49log76)log35log23log52(49a)bln2ln5×ln3ln2(49a)bln3ln5(49a)ln5ln3×ln3ln549a=pln49p=alnp2ln7=a=ln6ln7lnp=2ln6=ln62p=36

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