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4sin-6-4cos-6-3cos-2-2-




Question Number 111427 by weltr last updated on 03/Sep/20
4sin^6 α + 4cos^6 α − 3cos^2 2α
$$\mathrm{4sin}\:^{\mathrm{6}} \alpha\:+\:\mathrm{4cos}\:^{\mathrm{6}} \alpha\:−\:\mathrm{3cos}\:^{\mathrm{2}} \mathrm{2}\alpha \\ $$
Commented by Dwaipayan Shikari last updated on 03/Sep/20
Question no 111426

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