Question Number 111427 by weltr last updated on 03/Sep/20
$$\mathrm{4sin}\:^{\mathrm{6}} \alpha\:+\:\mathrm{4cos}\:^{\mathrm{6}} \alpha\:−\:\mathrm{3cos}\:^{\mathrm{2}} \mathrm{2}\alpha \\ $$
Commented by Dwaipayan Shikari last updated on 03/Sep/20
Question no 111426