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4x-2-1-x-3-dx-




Question Number 164685 by Zaynal last updated on 20/Jan/22
∫4x^2  (1−x)^3  dx
$$\int\mathrm{4}\boldsymbol{{x}}^{\mathrm{2}} \:\left(\mathrm{1}−\boldsymbol{{x}}\right)^{\mathrm{3}} \:\boldsymbol{{dx}} \\ $$
Answered by Ar Brandon last updated on 20/Jan/22
=4∫(1−x−1)^2 (1−x)^3 dx  =4∫[(1−x)^5 −2(1−x)^4 +(1−x)^3 ]dx
$$=\mathrm{4}\int\left(\mathrm{1}−{x}−\mathrm{1}\right)^{\mathrm{2}} \left(\mathrm{1}−{x}\right)^{\mathrm{3}} {dx} \\ $$$$=\mathrm{4}\int\left[\left(\mathrm{1}−{x}\right)^{\mathrm{5}} −\mathrm{2}\left(\mathrm{1}−{x}\right)^{\mathrm{4}} +\left(\mathrm{1}−{x}\right)^{\mathrm{3}} \right]{dx} \\ $$

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