Menu Close

4x-2-xy-y-2-dx-4y-2-3xy-x-2-dy-0-




Question Number 93530 by Shakhzod last updated on 13/May/20
(4x^2 +xy+y^2 )dx+(4y^2 +3xy+x^2 )dy=0
$$\left(\mathrm{4}{x}^{\mathrm{2}} +{xy}+{y}^{\mathrm{2}} \right){dx}+\left(\mathrm{4}{y}^{\mathrm{2}} +\mathrm{3}{xy}+{x}^{\mathrm{2}} \right){dy}=\mathrm{0} \\ $$
Commented by Shakhzod last updated on 13/May/20
Sorry.))
$$\left.{S}\left.{orry}.\right)\right) \\ $$$$ \\ $$$$ \\ $$
Commented by Shakhzod last updated on 13/May/20
That′s fixed it.
$${That}'{s}\:{fixed}\:{it}. \\ $$
Commented by Shakhzod last updated on 13/May/20
Did you see?
$${Did}\:{you}\:{see}? \\ $$
Commented by mr W last updated on 13/May/20
now you can solve it with y=xu.
$${now}\:{you}\:{can}\:{solve}\:{it}\:{with}\:{y}={xu}. \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *