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4x-3-dx-2x-2-2x-3-




Question Number 65307 by divyajyoti last updated on 28/Jul/19
∫(((4x+3)dx)/( (√(2x^2 +2x−3)))) = ?
(4x+3)dx2x2+2x3=?
Answered by divyajyoti last updated on 28/Jul/19
=∫(dt/( (√t)))+(1/( (√2)))∫(dx/( (√((x+(1/2))^2 −(((√7)/2))^2 ))))  =2(√(2x^2 +2x−3))+        (1/( (√2)))ln ∣x+(1/2)+(√(x^2 +x−(3/2)))∣+c .
=dtt+12dx(x+12)2(72)2=22x2+2x3+12lnx+12+x2+x32+c.
Commented by divyajyoti last updated on 28/Jul/19
(new user)I solved it myself, hahaha!  just learning how to use the app.
(newuser)Isolveditmyself,hahaha!justlearninghowtousetheapp.

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