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4x-x-3-t-t-1-3-dt-




Question Number 192858 by josemate19 last updated on 29/May/23
∫_(4x) ^( x^3 ) (√((√t)+t^(1/3) ))dt
4xx3t+t1/3dt
Answered by Frix last updated on 29/May/23
∫(√((√t)+(t)^(1/3) ))dt=  =((4(√(1+(t)^(1/6) )))/(15015))(3003t^(7/6) +231t−252t^(5/6) +280t^(2/3) −320t^(1/2) +384t^(1/3) −512t^(1/6) +1024) +C  Now do me a favour and insert the borders  for yourself!
t+t3dt==41+t615015(3003t76+231t252t56+280t23320t12+384t13512t16+1024)+CNowdomeafavourandinsertthebordersforyourself!

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