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4x-x-6-log-1-3-x-4-1-2-x-2-2-x-0-




Question Number 79497 by john santu last updated on 25/Jan/20
(((4x−∣x−6∣)(log_(1/3) (x+4)+1))/2^(x^2 −2^(∣x∣) ) )≥0
(4xx6)(log13(x+4)+1)2x22x0
Answered by john santu last updated on 25/Jan/20
(((4x−∣x−6∣)((1/3)−1)(x+4−3))/((2−1)(x^2 −∣x∣)))≥0  ÷ (−(2/3))    (((4x−∣x−6∣)(x+1))/(∣x∣(∣x∣−1)))≤0  (((4x−∣x−6∣)(x+1))/(∣x∣(x−1)(x+1)))≤0  ((4x−∣x−6∣)/(x−1))≤0 , x≠−1, x≠0 , x>−4  ((x−1.2)/(x−1)) ≤0 ⇒ x∈(1, (6/5)]
(4xx6)(131)(x+43)(21)(x2x)0\boldsymbol÷(23)(4xx6)(x+1)x(x1)0(4xx6)(x+1)x(x1)(x+1)04xx6x10,x1,x0,x>4x1.2x10x(1,65]
Commented by jagoll last updated on 26/Jan/20
mr. how to get 4x−∣x−6∣ = x−1.2?
mr.howtoget4xx6=x1.2?mr.howtoget4xx6=x1.2?

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