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4x-x-6-log-1-3-x-4-1-2-x-2-2-x-0-

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Question Number 79497 by john santu last updated on 25/Jan/20
(((4x−∣x−6∣)(log_(1/3) (x+4)+1))/2^(x^2 −2^(∣x∣) ) )≥0
(4x−∣x−6∣)(log13(x+4)+1)2x2−2∣x∣⩾0
Answered by john santu last updated on 25/Jan/20
(((4x−∣x−6∣)((1/3)−1)(x+4−3))/((2−1)(x^2 −∣x∣)))≥0 ÷ (−(2/3)) (((4x−∣x−6∣)(x+1))/(∣x∣(∣x∣−1)))≤0 (((4x−∣x−6∣)(x+1))/(∣x∣(x−1)(x+1)))≤0 ((4x−∣x−6∣)/(x−1))≤0 , x≠−1, x≠0 , x>−4 ((x−1.2)/(x−1)) ≤0 ⇒ x∈(1, (6/5)]
(4x−∣x−6∣)(13−1)(x+4−3)(2−1)(x2−∣x∣)⩾0÷(−23)(4x−∣x−6∣)(x+1)∣x∣(∣x∣−1)⩽0(4x−∣x−6∣)(x+1)∣x∣(x−1)(x+1)⩽04x−∣x−6∣x−1⩽0,x≠−1,x≠0,x>−4x−1.2x−1⩽0⇒x∈(1,65]
Commented by jagoll last updated on 26/Jan/20
mr. how to get 4x−∣x−6∣ = x−1.2?
mr.howtoget4x−∣x−6∣=x−1.2?

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