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4x-y-11-2y-5x-5-x-2z-9-z-y-x-




Question Number 20798 by ANTARES_VY last updated on 03/Sep/17
 { ((4x−y=11)),((2y+5x=5)),((x−2z=9)) :}    z+y−x=?
$$\begin{cases}{\mathrm{4}\boldsymbol{{x}}−\boldsymbol{{y}}=\mathrm{11}}\\{\mathrm{2}\boldsymbol{{y}}+\mathrm{5}\boldsymbol{{x}}=\mathrm{5}}\\{\boldsymbol{{x}}−\mathrm{2}\boldsymbol{{z}}=\mathrm{9}}\end{cases}\:\:\:\:\boldsymbol{{z}}+\boldsymbol{{y}}−\boldsymbol{{x}}=? \\ $$

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